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Proof step 23 from proof even-add (
previous step
)
(∃ m0. 2 * m0 = m) ∧ (∃ m0. 2 * m0 = n) ∨ ¬(∃ m0. 2 * m0 = m) ∧ ¬(∃ m0. 2 * m0 = n) ⊦ ∃ m0. 2 * m0 = m + n
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 24
:
2 * m0 = m ∧ 2 * m1 = n ∨ ¬(∃ m0. 2 * m0 = m) ∧ ¬(∃ m0. 2 * m0 = n) ⊦ ∃ m0. 2 * m0 = m + n
Rule argument
Additional information