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Proof step 26 from proof even-add (previous step)

⊦ ∃ m0. 2 * m0 = m + n, ∃ m0. 2 * m0 = n, ∃ m0. 2 * m0 = m

User applied rule exists right

And obtained the following new goals

Proof step 27:
⊦ 2 * (m / 2 + n / 2 + 1) = m + n, ∃ m0. 2 * m0 = n, ∃ m0. 2 * m0 = m

Rule argument

pos: right 1 terms: m / 2 + n / 2 + 1 abort: F discard: T computed: F

Additional information

Used terms: m / 2 + n / 2 + 1