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Proof step 3 from proof even-add (previous step)

∃ m0. 2 * m0 = m + n ⊦ (∃ m0. 2 * m0 = m) ∧ (∃ m0. 2 * m0 = n) ∨ ¬(∃ m0. 2 * m0 = m) ∧ ¬(∃ m0. 2 * m0 = n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information