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Proof step 32 from proof even-add (previous step)

⊦ odd(n), (2 * m / 2 + 2 * n / 2) + 2 = m + n, ∃ m0. 2 * m0 = n, ∃ m0. 2 * m0 = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
⊦ 2 * m / 2 + 2 = m, ∃ m0. 2 * m0 = m, ∃ m. 2 * m = 2 * m0

Rule argument

Additional information

Used simplifier rules: oe: ⊦ ¬ odd(n) ↔ even(n);%Even: ⊦ even(n) ↔ (∃ m. m + m = n);%eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%two-mdiv2-02: ⊦ (2 * m) / 2 = m; from specification nat-div%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-02: ⊦ m + m = 2 * m; from specification nat-mult