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Proof step 18 from proof even-mult (previous step)

2 * m0 = m ∨ 2 * m1 = n ⊦ ∃ m0. 2 * m0 = m * n

User applied rule case distinction

And obtained the following new goals

Proof step 19:
2 * m0 = m ⊦ ∃ m0. 2 * m0 = m * n
Proof step 21:
2 * m1 = n ⊦ ∃ m0. 2 * m0 = m * n

Rule argument

pos: left 1

Additional information