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Proof step 11 from proof max-a (previous step)

n < m, n0 ≤ m, n < n0 ⊦ n0 = 0, m = max(max(m, n), n0), m = 0

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 12:
max(m, n) < n0, n < m, n0 ≤ m, n < n0 ⊦ n0 = 0, m = max(max(m, n), n0), m = 0
Proof step 14:
n < m, n0 ≤ m, n < n0 ⊦ max(m, n) < n0, n0 = 0, m = max(max(m, n), n0), m = 0

Rule argument

fma: max(m, n) < n0

Additional information

Used formulas: max(m, n) < n0