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Proof step 15 from proof max-a (previous step)

n < max(m, n), n0 ≤ max(m, n), n < n0, n0 ≤ m, n < m ⊦ m = max(m, n), n0 = 0, m = 0, max(m, n) = 0

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: m < n

Additional information

Used simplifier rules: Max-left: ⊦ m < n → max(m, n) = n;%Max-right: ⊦ ¬ m < n → max(m, n) = m;%ls-02: ⊦ m < n → ¬ n < m; from specification nat-basic1 Used formulas: m < n