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Proof step 21 from proof max-a (previous step)

n ≤ m, n0 ≤ n, n0 ≤ m, n0 ≤ max(m, n) ⊦ m = max(m, n)

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: m < n

Additional information

Used simplifier rules: Max-left: ⊦ m < n → max(m, n) = n;%Max-right: ⊦ ¬ m < n → max(m, n) = m;%le-ls-simp: ⊦ m ≤ n → (n < m ↔ false); from specification nat Used formulas: m < n