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Proof step 1 from proof min-a (conclusion)

⊦ min(m, min(n, n0)) = min(min(m, n), n0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 2:
m < min(n, n0) ⊦ min(m, min(n, n0)) = min(min(m, n), n0)
Proof step 4:
⊦ m < min(n, n0), min(m, min(n, n0)) = min(min(m, n), n0)

Rule argument

fma: m < min(n, n0)

Additional information

Used formulas: m < min(n, n0)