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Proof step 13 from proof min-a (previous step)

n0 ≤ m, n0 ≤ n ⊦ n0 = min(min(m, n), n0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 14:
min(m, n) < n0, n0 ≤ m, n0 ≤ n ⊦ n0 = min(min(m, n), n0)

Rule argument

fma: min(m, n) < n0

Additional information

Used simplifier rules: Min-right: ⊦ ¬ m < n → min(m, n) = n; Used formulas: min(m, n) < n0