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Proof step 5 from proof min-a (previous step)

min(n, n0) ≤ m ⊦ min(n, n0) = min(min(m, n), n0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 6:
n < n0, min(n, n0) ≤ m ⊦ min(n, n0) = min(min(m, n), n0)
Proof step 12:
min(n, n0) ≤ m ⊦ n < n0, min(n, n0) = min(min(m, n), n0)

Rule argument

fma: n < n0

Additional information

Used formulas: n < n0