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Proof step 18 from proof odd-add (previous step)

⊦ odd(m), 2 * m / 2 = m, ∃ m0. 2 * m0 = 2 * m1 + m + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
⊦ ∃ m1. 2 * m1 = 2 * m0, ∃ m2. 2 * m2 = 2 * m1 + 2 * m0 + 1

Rule argument

Additional information

Used simplifier rules: pot2-even-02: ⊦ n / 2 * 2 = n ↔ even(n);%Even: ⊦ even(n) ↔ (∃ m. m + m = n);%oe: ⊦ ¬ odd(n) ↔ even(n);%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-02: ⊦ m + m = 2 * m; from specification nat-mult