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Proof step 30 from proof odd-add (previous step)

m0 = n0 + m1 ∧ m1 ≤ m0, 2 * m0 = m + 2 * m1 ⊦ 2 * n0 = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 31:
2 * (n0 + m1) = m + 2 * m1 ⊦ 2 * n0 = m

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lep: ⊦ m ≤ m + n; from specification nat