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Proof step 16 from proof odd-mult (previous step)

2 * m0 = m * 2 * m1 + m ⊦ ∃ m0. 2 * m0 = m

User applied rule exists right

And obtained the following new goals

Rule argument

pos: right 1 terms: m0 - m * m1 abort: F discard: T computed: F

Additional information

Used terms: m0 - m * m1