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Proof step 1 from proof odd (conclusion)

⊦ n ≤ 1 → (odd(n) ↔ n = 1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Odd: ⊦ odd(n) ↔ ¬ even(n);%Even: ⊦ even(n) ↔ (∃ m. m + m = n);%oone: ⊦ odd(1);%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%two-zero-01: ⊦ 2 * m = 0 ↔ m = 0; from specification nat-mult%one-01: ⊦ m < 1 ↔ m = 0; from specification nat-basic1%lels-02: ⊦ m ≠ n → (m ≤ n ↔ m < n); from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-02: ⊦ m + m = 2 * m; from specification nat-mult