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Proof step 2 from proof fin-inject-embed (previous step)

⊦ ⌜n∞.n⌝ = n∞, n∞ = ∞

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
⊦ n∞ ≠ ∞ → (n = n∞.n ↔ n∞ = ⌜n⌝ )

Rule argument

spec: nat-inf-basic inst: name: elim seq: ⊦ n∞ ≠ ∞ → (m = n∞.n ↔ n∞ = ⌜m⌝ ) subst: [n∞, m] → [n∞, m] flags: rewrite, current

Additional information

Used terms: n∞, m