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Proof step 5 from proof add-cancel-01 (previous step)

(⌜n0⌝ + ⌜1⌝ ) + n∞1 = (⌜n0⌝ + ⌜1⌝ ) + n∞2, ⌜n0⌝ + n∞1 + ⌜1⌝ = ⌜n0⌝ + n∞2 + ⌜1⌝ → n∞1 + ⌜1⌝ = n∞2 + ⌜1⌝ ⊦ n∞1 = n∞2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
(⌜n0⌝ + ⌜1⌝ ) + n∞1 = (⌜n0⌝ + ⌜1⌝ ) + n∞2, n∞1 + ⌜1⌝ = n∞2 + ⌜1⌝ ⊦ n∞1 = n∞2

Rule argument

Additional information

Used simplifier rules: add-assoc: ⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2;%add-comm: ⊦ n∞1 + n∞2 = n∞2 + n∞1;