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Proof step 1 from proof add-ls-cancel-num-04 (conclusion)

⊦ m ≤ n → (⌜(* m)⌝ + n∞2 < ⌜(* n)⌝ + n∞1 ↔ n∞2 < ⌜n - m⌝ + n∞1)

Special step normalize

And obtained the following new goals

Proof step 2:
⊦ m ≤ n → (⌜m⌝ + n∞2 < ⌜n⌝ + n∞1 ↔ n∞2 < ⌜n - m⌝ + n∞1)