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Proof step 1 from proof eqsucc-notls (conclusion)

⊦ n∞0 + ⌜1⌝ = n∞ → (n∞ < n∞0 ↔ false)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: add-not-less: ⊦ ¬ n∞ + n∞1 < n∞1;%add-assoc: ⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2;%add-comm: ⊦ n∞1 + n∞2 = n∞2 + n∞1;