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Proof step 2 from proof prime-add-fin (previous step)

⌜m0⌝ ≠ ∞ ⊦ (⌜m⌝ + ⌜m0⌝ ).n = m + ⌜m0⌝ .n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ (⌜m⌝ + ⌜m0⌝ ).n = m + m0

Rule argument

Additional information

Used simplifier rules: disj: ⊦ ⌜m⌝ ≠ ∞; from specification nat-inf-basic%sel: ⊦ ⌜m⌝ .n = m; from specification nat-inf-basic