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Proof step 1 from proof rem-seln-on-add (conclusion)

⊦ n∞ = ⌜m⌝ + ⌜n⌝ → n∞.n = m + n

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: prime-add-fin: n∞ ≠ ∞ ⊦ (⌜m⌝ + n∞).n = m + n∞.n;%add-assoc: ⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2;%add-comm: ⊦ n∞1 + n∞2 = n∞2 + n∞1;%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2%sel: ⊦ ⌜m⌝ .n = m; from specification nat-inf-basic%disj: ⊦ ⌜m⌝ ≠ ∞; from specification nat-inf-basic