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Proof step 1 from proof sum-zero-fin (conclusion)

⊦ ⌜n⌝ + n∞ = ⌜0⌝ ↔ n∞ = ⌜0⌝ ∧ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⌜n⌝ + n∞ = ⌜0⌝ ⊦ n∞ = ⌜0⌝ ∧ n = 0

Rule argument

Additional information

Used simplifier rules: num-add: ⊦ ⌜(* n)⌝ + ⌜(* m)⌝ = ⌜n + m⌝ ;%add-assoc: ⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2;%add-comm: ⊦ n∞1 + n∞2 = n∞2 + n∞1;%inj: ⊦ ⌜m⌝ = ⌜m0⌝ ↔ m = m0; from specification nat-inf-basic%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2