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Proof step 4 from proof eq (previous step)

m1 * m0 + m0 = n * m0, ∀ m0, n. m1 * m0 = n * m0 → m0 = 0 ∨ m1 = n ⊦ m0 = 0, m1 + 1 = n

User applied rule all left

And obtained the following new goals

Proof step 5:
m1 * m0 + m0 = n * m0, m1 * m0 = n -1 * m0 → m0 = 0 ∨ m1 = n -1, ∀ m0, n. m1 * m0 = n * m0 → m0 = 0 ∨ m1 = n ⊦ m0 = 0, m1 + 1 = n

Rule argument

pos: left 2 terms: m0, n -1 abort: F discard: F computed: F

Additional information

Used terms: m0, n -1