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Proof step 3 from proof le-03 (previous step)

⊦ m +1 * n ≤ m * n0 + n0 ↔ n ≤ n0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ m +1 * n = m * n + n
Proof step 5:
⊦ m +1 * n ≤ m +1 * n0 ↔ n ≤ n0

Rule argument

spec: nat-mult inst: name: rsucc seq: ⊦ m +1 * n = m * n + n subst: [n, m] → [n0, m] flags: rewrite, current

Additional information

Used terms: n0, m