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Proof step 3 from proof le-04 (
previous step
)
m ≤ n ⊦ n0 = 0, n * n0 ≤ m ↔ n0 = 0 ∨ n0 = 1 ∧ m = n ∨ n = 0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
m ≤ n ⊦ n0 = 0, n * n0 ≤ m ↔ n0 = 1 ∧ m = n ∨ n = 0
Rule argument
Additional information