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Proof step 1 from proof le-num (conclusion)
0 ≠ m ⊦ (* m) * n ≤ m * n0 ↔ n ≤ n0
Special step normalize
And obtained the following new goals
Proof step 2
:
0 ≠ m ⊦ m * n ≤ m * n0 ↔ n ≤ n0