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Proof step 2 from proof le-same (previous step)

⊦ m * n + n0 ≤ m ↔ n = 0 ∧ n0 ≤ m ∨ m = 0 ∧ n0 = 0 ∨ n = 1 ∧ n0 = 0

User applied rule case distinction

And obtained the following new goals

Proof step 3:
m * n + n0 ≤ m ⊦ n = 0 ∧ n0 ≤ m ∨ m = 0 ∧ n0 = 0 ∨ n = 1 ∧ n0 = 0
Proof step 11:
n = 0 ∧ n0 ≤ m ∨ m = 0 ∧ n0 = 0 ∨ n = 1 ∧ n0 = 0 ⊦ m * n + n0 ≤ m

Rule argument

pos: right 1

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