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Proof step 3 from proof le2-04 (previous step)

2 * n ≤ 2 * m + 1 ⊦ n ≤ m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
2 * n ≤ 2 * m + 1, m < n ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat