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Proof step 2 from proof ls-02 (previous step)

⊦ m0 * m < m0 * n ↔ m < n, m0 = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ m0 ≠ 0 → (m0 * m ≤ m0 * n ↔ m ≤ n)
Proof step 4:
m0 ≠ 0 → (m0 * n ≤ m0 * m ↔ n ≤ m) ⊦ m0 * m < m0 * n ↔ m < n, m0 = 0

Rule argument

spec: inst: name: le seq: ⊦ m0 ≠ 0 → (m0 * m ≤ m0 * n ↔ m ≤ n) subst: [m0, m, n] → [m0, n, m] flags: current, []

Additional information

Used terms: m0, n, m