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Proof step 4 from proof modeq (previous step)

(m1 * n + n) + n0 = m0 * n + n1, n0 < n, n1 < n, ∀ n, n0, m0, n1. m1 * n + n0 = m0 * n + n1 ∧ n0 < n ∧ n1 < n → n = 0 ∨ m1 = m0 ∧ n0 = n1 ⊦ n = 0, m1 + 1 = m0 ∧ n0 = n1

User applied rule all left

And obtained the following new goals

Proof step 5:
(m1 * n + n) + n0 = m0 * n + n1, n0 < n, n1 < n, m1 * n + n0 = m0 -1 * n + n1 ∧ n0 < n ∧ n1 < n → n = 0 ∨ m1 = m0 -1 ∧ n0 = n1 ⊦ n = 0, m1 + 1 = m0 ∧ n0 = n1

Rule argument

pos: left 4 terms: n, n0, m0 -1, n1 abort: F discard: T computed: F

Additional information

Used terms: n, n0, m0 -1, n1