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Proof step 4 from proof modls-03 (previous step)

n2 < n, m * n + n2 ≤ (n * m0 + n) + n1, n1 < n, m0 + 1 < m, ∀ m1, n0, n3, n4. ¬ m1 * n0 + n3 ≤ m0 * n0 + n4 ∨ ¬ n4 < n0 ∨ ¬ m0 < m1 ∨ ¬ n3 < n0 ⊦

User applied rule all left

And obtained the following new goals

Proof step 5:
n2 < n, m * n + n2 ≤ (n * m0 + n) + n1, n1 < n, m0 + 1 < m, ¬ m -1 * n + n2 ≤ m0 * n + n1 ∨ ¬ n1 < n ∨ ¬ m0 < m -1 ∨ ¬ n2 < n ⊦

Rule argument

pos: left 5 terms: m -1, n, n2, n1 abort: F discard: T computed: F

Additional information

Used terms: m -1, n, n2, n1