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Proof step 1 from proof modls (conclusion)

⊦ n0 < m0 → (m0 * m + n0 < m0 * n ↔ m < n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n0 < m0 ⊦ m0 * m + n0 < m0 * n ↔ m < n

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1