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Proof step 5 from proof modls (previous step)

m < n, n0 < m0 ⊦ m0 * m + n0 < m0 * n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
m0 * n ≤ m0 * m + n0, n0 < m0, m < n ⊦

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat