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Proof step 4 from proof modp (previous step)

n0 < m0, m1 + 1 < n, m0 * n ≤ (m0 * m1 + m0) + n0, ∀ n1, m, n2. ¬ m1 < n1 ∨ ¬ m * n1 ≤ m * m1 + n2 ∨ ¬ n2 < m ⊦

User applied rule all left

And obtained the following new goals

Proof step 5:
n0 < m0, m1 + 1 < n, m0 * n ≤ (m0 * m1 + m0) + n0, ¬ m1 < n -1 ∨ ¬ m0 * n -1 ≤ m0 * m1 + n0 ∨ ¬ n0 < m0, ∀ n1, m, n2. ¬ m1 < n1 ∨ ¬ m * n1 ≤ m * m1 + n2 ∨ ¬ n2 < m ⊦

Rule argument

pos: left 4 terms: n -1, m0, n0 abort: F discard: F computed: F

Additional information

Used terms: n -1, m0, n0