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Proof step 1 from proof mult-eq-succ-01 (conclusion)

⊦ m ≤ m1 → (m + 1 = m1 * m0 ↔ m0 = 1 ∧ m1 = m + 1 ∨ m = 1 ∧ m0 = 2 ∧ m1 = 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m ≤ m1 ⊦ m + 1 = m1 * m0 ↔ m0 = 1 ∧ m1 = m + 1 ∨ m = 1 ∧ m0 = 2 ∧ m1 = 1

Rule argument

Additional information