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Proof step 3 from proof numeral-10 (previous step)

m1 * m + n0 < m2 * m, m2 < m1 ⊦ m1 = 0, m2 = 0, m = 0

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 4:
∀ m, n0, m2. m0 * m + n0 < m2 * m ∧ m2 < m0 → m0 = 0 ∨ m2 = 0 ∨ m = 0, m0 +1 * m + n0 < m2 * m, m2 < m0 +1 ⊦ m0 +1 = 0, m2 = 0, m = 0

Rule argument

term: m1

Additional information

Used simplifier rules: nat freely generated by 0, +1;;