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Proof step 1 from proof one-01 (conclusion)

⊦ m0 * m = 1 ↔ m0 = 1 ∧ m = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m0 * m = 1 ⊦ m0 = 1 ∧ m = 1

Rule argument

Additional information

Used simplifier rules: mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;