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Proof step 2 from proof rdist (previous step)

⊦ m0 * m + m0 * n = m0 * (m + n)

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ m0, m. m0 * m + m0 * n0 = m0 * (m + n0) ⊦ m0 * m + m0 * n0 +1 = m0 * (m + n0 +1)

Rule argument

term: n

Additional information

Used simplifier rules: mult-base: ⊦ m * 0 = 0;%nat freely generated by 0, +1;;%add-base: ⊦ n + 0 = n; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2