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Proof step 1 from proof square-eq-02 (conclusion)
⊦ m * (m + 2) = n * (n + 2) ↔ m = n
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ m * (m + m0) = n * (n + m0) ↔ m = n
Rule argument
spec: nat-mult inst: name: square-eq-03 seq: ⊦ m * (m + m0) = n * (n + m0) ↔ m = n subst: [n, m0, m] → [n, 2, m] flags: rewrite, current
Additional information
Used terms: n, 2, m