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Proof step 1 from proof square-le-03 (conclusion)

⊦ m * (m + m0) ≤ n * (n + m0) ↔ m ≤ n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ m ≤ n ↔ ¬ n < m
Proof step 3:
⊦ ¬ n * (n + m0) < m * (m + m0) ↔ m ≤ n

Rule argument

spec: nat inst: name: le-def seq: ⊦ m ≤ n ↔ ¬ n < m subst: [n, m] → [n * (n + m0), m * (m + m0)] flags: rewrite

Additional information

Used terms: n * (n + m0), m * (m + m0)