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Proof step 5 from proof square-ls-04 (previous step)

n * n ≤ m * m, n ≤ m, m0 ≤ 2 * m, m * m + m0 < n * n ⊦ n = 0

User applied rule cut formula

And obtained the following new goals

Proof step 6:
n * n ≤ m * m, n ≤ m, m0 ≤ 2 * m, m * m + m0 < n * n ⊦ m * m + m0 < m * m, n = 0

Rule argument

fma: m * m + m0 < m * m

Additional information

Used simplifier rules: l-02: ⊦ ¬ m + n < m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used formulas: m * m + m0 < m * m