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Proof step 2 from proof square-ls-05 (previous step)

⊦ m * m + m * m0 < n * n + n * m0 ↔ m < n

User applied rule case distinction

And obtained the following new goals

Proof step 3:
m * m + m * m0 < n * n + n * m0 ⊦ m < n
Proof step 8:
m < n ⊦ m * m + m * m0 < n * n + n * m0

Rule argument

pos: right 1

Additional information