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Proof step 1 from proof three (conclusion)

⊦ m ≠ 1 → (m * m0 = 3 ↔ m = 3 ∧ m0 = 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m * m0 = 3 ⊦ m = 1, m = 3 ∧ m0 = 1

Rule argument

Additional information

Used simplifier rules: mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;