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Proof step 1 from proof two-succ-06 (conclusion)

⊦ 2 * m = 2 * n + m0 → ¬ m < n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
2 * m = 2 * n + m0, m < n ⊦

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1