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Proof step 14 from proof enc-invert (previous step)

maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ (((maxenc(m) - (m - n0)) + (m - n0)) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
n ≤ m ⊦ (m - n) + n = m
Proof step 16:
¬ m - n0 ≤ maxenc(m), maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ (((maxenc(m) - (m - n0)) + (m - n0)) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m
Proof step 34:
m - n0 ≤ maxenc(m), maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ (maxenc(m) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m

Rule argument

spec: nat inst: name: prop-01 seq: n ≤ m ⊦ (m - n) + n = m subst: [n, m] → [m - n0, maxenc(m)] flags: rewrite

Additional information

Used terms: m - n0, maxenc(m)