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Proof step 1 from proof exencode (conclusion)

⊦ ∃ m, n. encode(m, n) = n0

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: n0.1, n0.2 abort: F discard: T computed: F

Additional information

Used simplifier rules: enc-invert: ⊦ encode(m.1, m.2) = m; Used terms: n0.1, n0.2