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Proof step 5 from proof fst-nle (previous step)

m.1 ≤ m, n + m * m0 ≤ m.1, n + m * m0 ≤ m ⊦ m0 = 1, m0 = 0, m = 0 ∧ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ m + n = n + m
Proof step 7:
m.1 ≤ m, m * m0 + n ≤ m.1, m * m0 + n ≤ m ⊦ m0 = 1, m0 = 0, m = 0 ∧ n = 0

Rule argument

spec: nat-basic2 inst: name: c seq: ⊦ m + n = n + m subst: [n, m] → [m * m0, n] flags: rewrite

Additional information

Used terms: m * m0, n