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Proof step 1 from proof max-def-01 (conclusion)

⊦ (n * (n + 1)) / 2 ≤ m ∧ m < ((n + 1) * (n + 2)) / 2 → maxenc(m) = n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ maxenc(n) = maxenc(0, n)
Proof step 3:
⊦ (n * (n + 1)) / 2 ≤ m ∧ m < ((n + 1) * (n + 2)) / 2 → maxenc(0, m) = n

Rule argument

spec: nat-pair inst: name: maxi-start seq: ⊦ maxenc(n) = maxenc(0, n) subst: [n] → [m] flags: rewrite, current

Additional information

Used terms: m