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Proof step 9 from proof max-zero-01 (previous step)

1 ≤ m ⊦ maxenc(1, m) = 1 ↔ m = 1 ∨ m = 2, m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ ¬ ((m + 1) * (m + 2)) / 2 ≤ n → maxenc(m, n) = m
Proof step 11:
¬ ¬ ((1 + 1) * (1 + 2)) / 2 ≤ m, 1 ≤ m ⊦ maxenc(1, m) = 1 ↔ m = 1 ∨ m = 2, m = 0
Proof step 25:
¬ ((1 + 1) * (1 + 2)) / 2 ≤ m, 1 ≤ m ⊦ 1 = 1 ↔ m = 1 ∨ m = 2, m = 0

Rule argument

spec: nat-pair inst: name: maxi-found seq: ⊦ ¬ ((m + 1) * (m + 2)) / 2 ≤ n → maxenc(m, n) = m subst: [n, m] → [m, 1] flags: rewrite, current

Additional information

Used terms: m, 1