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Proof step 3 from proof 2-pot-mod (previous step)

2 ^ m0 % 2 = 0 ∨ m0 = 0 ⊦ 2 ^ m0 +1 % 2 = 0, m0 +1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
2 ^ m0 % 2 = 0 ⊦ 2 ^ (m0 + 1) % 2 = 0, m0 = 0

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%oz: ⊦ m + 1 ≠ 0; from specification nat-basic2%succ: ⊦ m +1 = m + 1; from specification nat-basic2